Question

Find the intercept of the line 13x+5y+12=0

Answer 1

Step-by-step explanation:

The required line is passing through the point (1, 1) and parallel to the line 13x + 5y + 12 = 0

Slope of the required line = -13/5

(y - y1) = m(x - x1)

(y - 1) = (-13/5)(x - 1)

5(y - 1) = -13(x - 1)

5y - 5 = -13x + 13

13x + 5y - 5 - 13 = 0

13x + 5y - 18 = 0