Question

find the intercept of the plane 4x+3y-2z+2=0 onthe co_ordrinate axes.

Answer 1

X=-1/2 Y=-2/3 Z=1
Of the plane 4x+3y-2z+2=0

Answer 2

Sol. Equation of the plane is 4x + 3y – 2z + 2 = 0

–4x – 3y + 2z = 2⇒ 4x 3y 2z x y z

-4x/2-3y/2+2z/2=1

X/(-1/2)+y/(-2/3)+2/1=1

x-intercept = –1/2, y-intercept = –2/3, z-intercept = 1.