Question

find the intercepts cut off by the line 2x-y+16=0 on the coordinate axis​

Answer 1

Answer:

The intercept of given line is ( - 8 , - 16 )  

Step-by-step explanation:

Given as :

The line equation is as

2 x + y + 16 = 0

For x-intercept  , put y = 0

So, The equation become

2 x + 0 + 16 = 0

Or, 2 x + 16 = 0

or, 2 x = -16

∴   x = $\dfrac{- 16}{2}$

i.e  x = - 8

Again

For y-intercept  , put x = 0

So, The equation become

2 × 0 + y + 16 = 0

Or, 0 + y + 16 = 0

or, y = -16

i.e y = - 16

Hence, The intercept of given line is ( - 8 , - 16 )  Answer

Answer 2

Answer:

The intercept of given line is ( - 8 , - 16 )

Step-by-step explanation:

Given as :

The line equation is as

2 x + y + 16 = 0

For x-intercept , put y = 0

So, The equation become

2 x + 0 + 16 = 0

Or, 2 x + 16 = 0

or, 2 x = -16

∴ x = \dfrac{- 16}{2}

2

−16

i.e x = - 8

Again

For y-intercept , put x = 0

So, The equation become

2 × 0 + y + 16 = 0

Or, 0 + y + 16 = 0

or, y = -16

i.e y = - 16

Hence, The intercept of given line is ( - 8 , - 16 ) Answer