Question

find the intercepts cut off by the plane 2x +y - z=5

Answer 1

Hey !!

The equation of the given plane is

               2x + y - z = 5

  $\frac{2}{5} x + \frac{y}{5} - \frac{z}{5} = 1$

 x/5/2 +  $\frac{y}{5} + \frac{z}{-5} = 1$

which is the form $\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1$ where a , b and c are intercepts on x, y and z-axis.

Thus, intercepts on x,y and z-axis are $\frac{5}{2} , 5$ and -5 respectively.

GOOD LUCK !!