Question

Find the intercepts made by the line 2x - 3y + 12 = 0 on the coordinate axis.​

Answer 1

Step-by-step explanation:

Given line equation is 2x−3y+12=0

On putting y=0, we will get the intercept made on x - axis

2x−3y+12=0

2x−3×0+12=0,

2x−0+2=0,

2x=−12

⇒x=−6

Now, on putting x=0, we get the intercepts made on y - axis

2x−3y+12=0

2×0−3y+12=0

−3y=−12

⇒y=4

Hence, the x - intercept and y - intercept of the given line is −6 and 4 respectively.

Answer 2

$\red{ \bold{ \underline{ \mathcal{Given: \: 2x - 3y + 12 = 0.}}}} \\ \red{ \tt:{ \implies{ \mathcal{2x - 3y = - 12.}}}} \\ \blue{ \bold{(Divide \: by \: - 12) </p><p></p><p> </p><p>, \: Then,}} \\ \red{ \tt:{ \implies { \mathcal{ \frac{x}{ - 6} + \frac{y}{ - 4} = 1}}}} \\ \green{(This \: equation \: is \: in \: the \: slope \: form. \: Which \: is \: in \: the \: form \: \frac{x}{a} + \frac{y}{b} = 1.Where \: a \: is \: x - coordinate \: and \: y - coordinate. )} \\ \red{ \therefore{ \underline{ \mathcal{(-6) \: is \: x - coordinate \: and \: (-4) \: is \: y - coordinate.}}}}$