Question

find the intercepts on the axis of the straight line passing through the points (1,-3) and (4,5).

Answer 1

the line passes through 1st and 4th quadrant

Answer 2

equation of points passing through (1,-3), (4,5)

$\bf\implies\dfrac{y-y_1}{y_2-y_1}$=$\bf\dfrac{x-x_1}{x_2-x_1}$

y+3/5+3 = x-1/4-1

y+3/8 = x-1/3

3y+9=8x-8

8x-3y-8-9=0

8x-3y-17=0

x-intercept = 17/8

y- intercept =17/-3 =>. -17/3

x/a+y/b=1

x/17/8 + y/-17/3 =1

8x/17 - 3y/17 =1

8x-3y=17

therefore equation is 8x-3y-17=0