Find the intercepts on the coordinate axis by the plane 2x-3y+5z=4
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The plane 2x+3y-4z=5 intersects the x-axis at (a,0,0), the y-axis at (0,b,0), and the Z-axis at (0,0,c).
Therefore, it is required for us to get the values of a, b and c.
Substitute with each co-ordinate in the equation of the plane:
1. (a,0,0):
2. (0,b,0):
3. (0,0,c):
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Answer:
Solution:
To find the intercepts on the coordinates axis,convert the equation into intercept form.
we know that standard intercept equation of plane is
here a,b,c are intercept of x,y and z axis respectively
So
So, x -axis intercept (2,0,0)
Y-axis intercept (0,-4/3,0)
z-axis intercept(0,0,4/5)
Hope it helps you.
Solution:
To find the intercepts on the coordinates axis,convert the equation into intercept form.
we know that standard intercept equation of plane is
here a,b,c are intercept of x,y and z axis respectively
So
So, x -axis intercept (2,0,0)
Y-axis intercept (0,-4/3,0)
z-axis intercept(0,0,4/5)
Hope it helps you.
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