find the interest and amount on rupees 1200 at the rate of 4.5% simple interest for 2.5 years
Answers
Answered by
1
Answer:
Rate =
P×T
S.I×100
P=1200−1000=200
S.I=30
T=3 years
Rate =
200×3
30×100
=
600
3000
=5%
Answered by
34
Answer:
Simple interest= P×R×T/100
= 1200×4.5×2.5/100
= Rs. 135
Amount= P+ interest
= 1200+135
= Rs. 1335
Similar questions