Question

Find the interest and the amount received on 3000 for 2 years at the rate of 11%p.a.​

Answer 1

Answer:

Given

principlal - 3000

time - 2 year

rate - 11 %

a/q

SI = p*r*t / 100

Si = 3000*2*11/100

= 660

and amount = 3000+660 = 3660 ans.

Answer 2

Given

• Principal = Rs 3000

• Time = 2 years

• Rate = 11 %

We Find

Simple interest

We Know

Formula used :-

$\boxed {\red{Simple\:Intrest= \frac{P×R×T}{100}}}$

According to the question

${\red{Simple\:Intrest= \frac{P×R×T}{100}}}$

${\red{Simple\:Intrest= \frac{3000×2×11}{100}}}$

${\red{Simple\:Intrest= \frac{66000}{100}}}$

${\red{Simple\:Intrest= \cancel\frac{66000}{100}}}$

${\red{Simple\:Intrest= 660}}$

So, Total Amount Recivied :-

Total Amount = 3000 + 660

Total Amount = Rs 3660

Hence, Simple Interest is Rs 660 And Total Amount Recivied is Rs 3660.