Question

. Find the interest for one year for the following
(a) P = ₹ 500, R = 7 °/•
( b) P = ₹ 750, R = 10 °/•
(c) P = ₹ 1300, R= 12 °/•
(d) P = ₹ 2300, R = 15 °/•
(g) P = ₹ 6050, R = 30 °/•
(h) P = ₹ 7200, R = 40 °/•
( I ) P = ₹ 9006,R = 50 °/•​

Answer 1

Step-by-step explanation:

a) Principal = Rs 6400, rate = 6% p.a. and time = 2 years

ANSWER:

P=Rs. 6400, R=6%, T=2 yearsS.I. =P×R×T100=6400×6×2100 =Rs. 768Amount=P+S.I.=6400+768= Rs. 7168

b) Principal = Rs 2650, rate = 8% p.a. and time = 212 years

ANSWER:

P=Rs. 2650, R=8%, T=212 years =52 years

S.I.= P×R×T100=2650×8×5100×2

=Rs. 530Amount=P+S.I.=2650+530=Rs. 3180

c) Principal = Rs 1500, rate = 12% p.a. and time = 3 years 3 months.

ANSWER:

P=Rs.1500, R=12%, T=3+312=134 years S.I.=P×R×T100=1500×12×13100×4 =Rs. 585Amount=P+S.I. =1500+585 =Rs. 2085

d) Principal = Rs 9600, rate = 712% p.a. and time = 5 months.

ANSWER:

P= Rs. 9600R=712% T=5 months =512 yearsS.I.=P×R×T100 =9600×15×5100×2×12 =Rs. 300Amount= P+ S.I.=9600+300=Rs. 9900

e) Principal = Rs 5000, rate = 9% p.a. and time = 146 days.

ANSWER:

P=Rs.5000 , R=9% , T=146 days=146365 yearsS.I.=P×R×T100=5000×9×146100×365 =Rs. 180Amount=P+S.I.=5000+180=Rs. 5180

f) Principal = Rs 6400, SI = Rs 1152 and rate = 6% p.a.

ANSWER:

P=Rs. 6400, S.I. = Rs. 1152, R=6% T =S.I.×100P×R=1152×1006400×6 =1152384 =3 years

g) Principal = Rs 9540, SI = Rs 1908 and rate = 8% p.a.

ANSWER:

P=Rs. 9540 , S.I.=Rs. 1908, R=8%T = S.I.×100P×R=1908×1009540×8 =104 =212 years

h) Principal = Rs 5000, amount = Rs 6450 and rate = 12% p.a.

ANSWER:

P=Rs. 5000, A=Rs. 6450, R=12% S.I.=A−P =6450−5000 =Rs. 1450T =S.I×100P×R=1450×1005000×12 =2912 =2512 =2 years 5 months

I) Principal = Rs 8250, SI = Rs 1100 and time = 2 years.

ANSWER:

P = Rs. 8250, S.I.=Rs. 1100, T=2 yearsR=S.I.×100P×T=1100×1008250×2 =1100165=6.67%

Answer 2

(a)

Given :

• Principal = ₹ 500
• Rate = 7%

To Find :

• The time.

Solution :

We know that if we are given the principal, rate and time and is asked to find the simple interest then our required formula is,

SI = (P × R × T)/100

where,

• P = ₹ 500
• R = 7%
• T = 1 year

Substituting the values,

⇒ SI = (500 × 7 × 1)/100

⇒ SI = (5 × 7 × 1)/1

⇒ SI = 5 × 7

⇒ SI = 35

∴ SI = ₹ 35.

The simple interest is ₹ 35.

(b)

Given :

• Principal = ₹ 750
• Rate = 10%

To Find :

• The time.

Solution :

We know that if we are given the principal, rate and time and is asked to find the simple interest then our required formula is,

SI = (P × R × T)/100

where,

• P = ₹ 750
• R = 10%
• T = 1 year

Substituting the values,

⇒ SI = (750 × 10 × 1)/100

⇒ SI = (75 × 1 × 1)/1

⇒ SI = 75

∴ SI = ₹ 75.

The simple interest is ₹ 75.

(c)

Given :

• Principal = ₹ 1300
• Rate = 12%

To Find :

• The time.

Solution :

We know that if we are given the principal, rate and time and is asked to find the simple interest then our required formula is,

SI = (P × R × T)/100

where,

• P = ₹ 1300
• R = 12%
• T = 1 year

Substituting the values,

⇒ SI = (1300 × 12 × 1)/100

⇒ SI = (13 × 12 × 1)/1

⇒ SI = 13 × 12

⇒ SI = 156

∴ SI = ₹ 156.

The simple interest is ₹ 156.

(d)

Given :

• Principal = ₹ 2300
• Rate = 15%

To Find :

• The time.

Solution :

We know that if we are given the principal, rate and time and is asked to find the simple interest then our required formula is,

SI = (P × R × T)/100

where,

• P = ₹ 2300
• R = 15%
• T = 1 year

Substituting the values,

⇒ SI = (2300 × 15 × 1)/100

⇒ SI = (23 × 15 × 1)/1

⇒ SI = 23 × 15

⇒ SI = 345

∴ SI = ₹ 345.

The simple interest is ₹ 345.

(e)

Given :

• Principal = ₹ 6050
• Rate = 30%

To Find :

• The time.

Solution :

We know that if we are given the principal, rate and time and is asked to find the simple interest then our required formula is,

SI = (P × R × T)/100

where,

• P = ₹ 6050
• R = 30%
• T = 1 year

Substituting the values,

⇒ SI = (6050 × 30 × 1)/100

⇒ SI = (605 × 3 × 1)/1

⇒ SI = 605 × 3

⇒ SI = 1815

∴ SI = ₹ 1,815.

The simple interest is ₹ 1,815.

(f)

Given :

• Principal = ₹ 7200
• Rate = 40%

To Find :

• The time.

Solution :

We know that if we are given the principal, rate and time and is asked to find the simple interest then our required formula is,

SI = (P × R × T)/100

where,

• P = ₹ 7200
• R = 40%
• T = 1 year

Substituting the values,

⇒ SI = (7200 × 40 × 1)/100

⇒ SI = (72 × 40 × 1)/1

⇒ SI = 72 × 40

⇒ SI = 2880

∴ SI = ₹ 2,880.

The simple interest is ₹ 2,880.

(g)

Given :

• Principal = ₹ 9006
• Rate = 50%

To Find :

• The time.

Solution :

We know that if we are given the principal, rate and time and is asked to find the simple interest then our required formula is,

SI = (P × R × T)/100

where,

• P = ₹ 9006
• R = 50%
• T = 1 year

Substituting the values,

⇒ SI = (9006 × 50 × 1)/100

⇒ SI = (9006 × 1 × 1)/2

⇒ SI = (4503 × 1 × 1)/1

⇒ SI = 4503

∴ SI = ₹ 4,503.

The simple interest is ₹ 4,503.