Question

find the interest of principal of Rs 1,200 at the rate of %9 per in one year​

Answer 1

Answer:

p = 1200

r = 9% p.a.

time = 1year

therefore S.I. = (p × r × t)/100

= (1200×9×1)/100

= 12×9×1

= 108

therefore, S.I. on Rs. 1200 = R.s. 108 Ans.

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Answer 2

Step-by-step explanation:

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