Question

Find the interest on ₹ 10,000 for 13/4 years at the rate of 3.4% p.a. Also, find the amount.​

Answer 1

Given :-

• Principal (P) = ₹ 10,000
• Time (t) = 13/4 years ↪3.25years.
• Rate of interest (R) = 3.4% p.a

To Find :-

• It's Amount and interest.

Solution :-

As we know that,

A = P(1 + R/100)^t

[ Putting values ]

↪ A = 10000(1 + 3.4/100)^3.25

↪ A = 10000(1 + 0.034)^3.25

↪ A = 10000(1.034)^3.25

↪ A = 10000(517/500)^13/4

↪ A = 10000(1.11479)

↪ A = ₹11147.9

.°. Amount = ₹ 11147.9 .

Now, we know that,

Interest = Amount - Principal

↪ Interest = ₹(11147.9 - 10000)

↪ Interest = ₹1147.9

.°. Interest = ₹ 1147.9 .

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}} </p><p></p><p>$

$\begin{gathered}\green{\therefore{\text{Simple\:interest=80\:dollars}}}\\\end{gathered} </p><p></p><p>$

$\begin{gathered}\green{\therefore{\text{Amount=720\:dollars}}}\\\end{gathered} </p><p>$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}} </p><p></p><p>$

$\begin{gathered}\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 1\:year} \\ \\ : \implies \text{Principal(p) =\ 640} \\ \\ : \implies \text{Rate(r) = 12.5\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}\end{gathered} </strong></p><p></p><p><strong>[tex]\begin{gathered}\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 1\:year} \\ \\ : \implies \text{Principal(p) =\ 640} \\ \\ : \implies \text{Rate(r) = 12.5\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}\end{gathered}$

• According to given question :

$\begin{gathered}\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies \sf{S.I = \frac{p \times r \times t}{100}} \\ \\ : \implies S.I = \frac{640\times 12.5\times1}{100} \\ \\ : \implies \sf{S.I = \frac{64\times12.5}{10}} \\ \\ \green{ : \implies \sf{S.I= \ 80}} \\ \\ \green{ \therefore \text{Simple\:interest =180\: dollars}} \\ \\ :\implies Amount= \sf{S.I+principal}\\\\ \green{:\implies\text{Amount=80+640=720\:dollars}} \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}\end{gathered} </p><p>$