Math, asked by kinjaljain7317, 3 months ago

Find the interest on 3600 at 12/5% per annum for a period of 3 years and 6
5
months.​

Answers

Answered by bhemakesh2
1

Answer:

Principal = Rs 9600, rate = 712% p.a. and time = 5 months. ... P=Rs 6000, R=12%, T=3 years 8 months = 3812=4412yearsS.I. =P×R×T100=6000×12×44100×12= Rs 2640A= P+S.I. ... The simple interest on a certain sum for 3 years at 10% per annum is Rs 829.50.

Step-by-step explanation:

Answered by chandalishaikh00
1

Answer:

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Maths

Ravi lends Rs.3600 on simple interest to harsh for a period of 5 years.He lends the part of the amount at 4% interest and the rest at 6% and receives Rs.960 as the amount of interest. how much money did he lend on 4% interest rate?

Answer

Let the money lend by Ravi to Harsh at 4% simple interest be Rsx.

Therefore, money lend by Ravi to Harsh at 6%

simple interest be Rs(3600−x)

as total amount lend is Rs3600.

Now simple intrest at 4% for 5 years

Principal (P)= Rs x, rate(R)=4% and Time (T)=5

SI =

100

PRT

=x×4×

100

5

=

100

20x

Now simple interest at 6% for 5 years

Principal (P)= Rs (3600−x), rate (R)=6% and Time (T)=5

SI=

100

PRT

=(3600−x)×6×

100

5

=(3600−x)×

100

30

=

100

(108000−30x)

Given that, total simple interest received = Rs 960.

Therefore, 960=

100

20x

+

100

(108000−30x)

⇒960×100=20x+108000−30x

⇒96000=108000−10x

⇒10x=108000−96000

⇒10x=12000

∴x=Rs1200

Money lend by Ravi on 4% interest rate is Rs1200

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