Math, asked by WARRIOR123321, 3 months ago

Find the interest on 3600 at 2
%
per annum for a period of 3 years and 6
months.​

Answers

Answered by rittikapannase
6

Answer:

For the first year

P=Rs36,000

N=1year

R=10 %

We have S.I.=

100

PNR

=

100

36,000×1×10

=Rs3,600

And Amount at the end of first year P+S.I.=Rs36,000+Rs3,600=Rs39,600

Now, for the second year

P=Rs39,600

N=1year

R=12 %

We have S.I.=

100

PNR

=

100

39,600×1×12

=Rs4,752

And Amount at the end of second year P+S.I.=Rs39,600+Rs4,752=Rs44,352

Similar questions