Find the interest on 3600 at 2
%
per annum for a period of 3 years and 6
months.
Answers
Answered by
6
Answer:
For the first year
P=Rs36,000
N=1year
R=10 %
We have S.I.=
100
PNR
=
100
36,000×1×10
=Rs3,600
And Amount at the end of first year P+S.I.=Rs36,000+Rs3,600=Rs39,600
Now, for the second year
P=Rs39,600
N=1year
R=12 %
We have S.I.=
100
PNR
=
100
39,600×1×12
=Rs4,752
And Amount at the end of second year P+S.I.=Rs39,600+Rs4,752=Rs44,352
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