Find the interest on a deposit it of ₹3650 from January 3,2006 at the rate of 10% p.a. up to march 17,2006.
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Answer :
P=₹3650
Rate =10%
Time= 29+28+16=73day
=73/365=1/5 year
Si=prt/100
=3650x10x(1/5)/100
=₹73
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