Math, asked by av123456, 4 months ago

Find the interest on rs 11680 from 15 January 2005 to 15 February 2006 at the rate of 10\3 % the answer is 421.22 give me the solution​

Answers

Answered by preetham2012
1

Answer:

60

120

90

180

Answer :

A

Solution :

Number of days from 1 January, 2007 to 15 March, 2007=73 days.

Time period =73 days.

`S.I. ("in Rs.")=(3000)((73)/(365))((10)/(100))=60`

Answered by Anonymous
60

Answer:

The interest = Rs 421.77

Step-by-step explanation:

Given :

  • Principal amount (P) = Rs 11,680

  • Interest rate (R) = 10/3 %

  • Time (T) = 13 months

(15 January 2005 to 15 February 2006)

To find :

  • Interest amount (SI)

Solution :

\boxed{\sf{SI=\dfrac{P \times \: R \: \times \: T}{100}}}

\sf{\longrightarrow \: \dfrac{11680 \: \times \frac{10}{3} \times \frac{13}{12}}{100}}

\sf{\longrightarrow \: 11680 \: \times \dfrac{1}{3} \: \times \: \dfrac{13}{12} \: \times \: \dfrac{1}{10}}

\sf{\longrightarrow \: 1168 \: \times \: \dfrac{1}{3} \: \times \: \dfrac{13}{12}}

\sf{\longrightarrow \: \dfrac{15,184}{36}}

\sf{\longrightarrow \: 421.77}

∴ The interest = Rs 421.77

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