Question

Find the interest on rs 11680 from 15 January 2005 to 15 February 2006 at the rate of 10\3 % the answer is 421.22 give me the solution​

Answer 1

Answer:

The interest = Rs 421.77

Step-by-step explanation:

Given :

Principal amount (P) = Rs 11,680

Interest rate (R) = 10/3 %

Time (T) = 13 months

(15 January 2005 to 15 February 2006)

To find :

Interest amount (SI)

Solution :

$\boxed{\sf{SI=\dfrac{P \times \: R \: \times \: T}{100}}}$

$\sf{\longrightarrow \: \dfrac{11680 \: \times \frac{10}{3} \times \frac{13}{12}}{100}}$

$\sf{\longrightarrow \: 11680 \: \times \dfrac{1}{3} \: \times \: \dfrac{13}{12} \: \times \: \dfrac{1}{10}}$

$\sf{\longrightarrow \: 1168 \: \times \: \dfrac{1}{3} \: \times \: \dfrac{13}{12}}$

$\sf{\longrightarrow \: \dfrac{15,184}{36}}$

$\sf{\longrightarrow \: 421.77}$

∴ The interest = Rs 421.77

Answer 2

Given :-

Time = 13 months

Rate = 10/3% per annum

Principal = 11680

To Find :-

Simple interest

Solution :-

We know that

$\sf SI = \dfrac{PRT}{100}$

SI = Simple interest

P = Principal

R = Rate

T = Time

$\sf SI = \dfrac{11680 \times 13 \times 10}{100 \times 3\times 12}$

SI = 1518400/3600

SI = 15184/36

SI = 421.22