Question

Find the interest on Rs. 1200 for one year at 10% per annum compounded half-yearly.

Answer 1

Step-by-step explanation:

S.I

= Rs.(1200x10x1/100)

= Rs.120.

C.I

= Rs[(1200x1+5/100)² -1200]

= Rs.123.

Difference

= Rs.[123-120]

= Rs. 3.

Answer 2

$\bold\green{SI}$

= Rs. (1200×10×1/100)

= Rs. 120

$\bold\green{CI}$

= Rs [(1200×1+5)^2–1200]

= Rs 123

$\bold\green{Difference}$

= Rs [123–120]

= Rs 3