Question

find the interest rupees at 2 2 by 5% per annum for a period of 3 years and 6 months

Answer 1

Answer:

Given -

Time given = \sf{ 2\dfrac{1}{2}}2

2

1

and hours and 2 hours.

Distance given = 90 km

To find -

Time taken in part a and distance coveres in part b.

Solution -

In the question, we are provided with the distance and time in part a and time in part b. And we need to find the time taken in part a and distance covered in part b. For that, first in part a, we will convert the given time into minutes and then, we will solve the further question, and for part b, we will take the values from part a into part b, then we will solve the further question. Let's do it !

For Part A -

Distance, d = 90km

Time, t = \sf{2\dfrac{1}{2}}2

2

1

= 150 minutes.

So -

Time taken to cover 90km is 150 mins therefore, it will take \sf\frac{150}{90}

90

150

mins to cover 1km.

Now -

We will equate the whole thing, we have obtained from above.

→ Time taken = Time taken in 1km × Total distance covered.

→ Time taken = 150/90 × 30

→ Time taken = 15/9 × 30

→ Time taken = 50 mins

\therefore∴ It will taken 50 mins to cover 30km.

For Part B -

Distance covered = D

Time taken = \sf{2\dfrac{1}{2}}2

2

1

= 5/2 hours.

So -

5/2 hours are taken to cover 90km for part b, so the distance covered in 1km will be written as -

→ Distance coveres in 1km = 90 ÷ 5/2

→ Distance coveres in 1km = 2/5 × 90

→ Distance coveres in 1km = 36km

So -

Distance covered in 2 hours, will be written as -

→ Distance covered in 2 hours = 2 × 36km

→ Distance covered in 2 hours = 72 km

\therefore∴ In 2 hours, 72km distance will be covered.

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