Question

find the intergal root of the polynomial f(x)=xcube+6xsquar +11x+6

Answer 1

hyy dear....

here Ur answer is....

putting x =1
(1)^3 -6(1)^2+11(1)-6=0
one root is (x-1)
divide whole eqn by (x-1)
(x-1) | x^3 -6x^2 + 11x -6 | X^2 -5x +6
x^3 -x^2
=======
-5x^2 +11x-6
-5x^2+5x
========
6x-6
6x-6
=====
0
so eqn is x^2-5x+6=0
x^2-2x-3x+6=0
(x-2)(x-3)=0
so the roots are 1 ,2,3

HOPE THIS WILL HELP U ✌️✌️