Question

find the intrest and the amount in the following cases $ 10000 for 3 year at 5/ per a​

Answer 1

Question :-

find the interest and the amount in the following cases $ 10000 for 3 years at the rate of 5% per annum.

Answer :-

• Simple interest = 1500.
• The total amount = 11,500.

Given :-

• The principal = $10000
• Rate = 5%
• Time = 3 years.

To find :-

• The simple interest.
• The total amount.

Step by step explanation :-

As we know , We need to find simple interest by the data given to us. To find simple interest, There is a forumla let's see the formula and know how to do it :

Formula:

$\boxed{ \mathfrak{ S.I = \dfrac{ Principal \times Rate \times Time}{100} }}$

Solution:

By applying the formula , We get :

$\bf{ S.I = \dfrac{10000 \times 5 \times 3}{100} }$

First cute off all the zeros , We have :

$\bf{ S.I = \dfrac{100 \times 5 \times 3}{1} }$

Now, We will multiply the remaining numbers.

$\bf S.I = 100 \times 5 \times 3$

$\bf S.I = 1500$

So, The simple interest is $1500.

Now, For amount:

Let's use this formula :

$\boxed{ \mathfrak { Amount = Principal + Interest }}$

By applying this formula, We get :

$\bf Amount = 10000 + 1500 = Rs \: 11,500.$

So, The amount is 11,500.

Answer 2

Question :-

find the interest and the amount in the following cases $ 10000 for 3 years at the rate of 5% per annum.

Answer :-

Simple interest = 1500.

The total amount = 11,500.

Given :-

The principal = $10000

Rate = 5%

Time = 3 years.

To find :-

The simple interest.

The total amount.

Step by step explanation :-

As we know , We need to find simple interest by the data given to us. To find simple interest, There is a forumla let's see the formula and know how to do it :

Formula:

\boxed{ \mathfrak{ S.I = \dfrac{ Principal \times Rate \times Time}{100} }}

S.I=

100

Principal×Rate×Time

Solution:

By applying the formula , We get :

\bf{ S.I = \dfrac{10000 \times 5 \times 3}{100} }S.I=

100

10000×5×3

First cute off all the zeros , We have :

\bf{ S.I = \dfrac{100 \times 5 \times 3}{1} }S.I=

1

100×5×3

Now, We will multiply the remaining numbers.

\bf S.I = 100 \times 5 \times 3S.I=100×5×3

\bf S.I = 1500S.I=1500

So, The simple interest is $1500.

Now, For amount:

Let's use this formula :

\boxed{ \mathfrak { Amount = Principal + Interest }}

Amount=Principal+Interest

By applying this formula, We get :

\bf Amount = 10000 + 1500 = Rs \: 11,500.Amount=10000+1500=Rs11,500.

So, The amount is 11,500.