Question

Find the inverse of function
$f(x)= \frac{x^2-4x+2}{3x}$

Answer 1

as for inverse function
$f(f^{-1}(x))=x$
take [tex]f^{-1}(x)=y [/tex]
therefore
$\frac{y^2-4y+2}{3y}=x \\ y^2-4y+2=3xy \\ y^2-4y=(3x+4)y \\ (y-4)=3x+4 \\ y=3x+8$
therefore inverse function is 3x+8