Question

find the jcf of a and b where 72=2^a×3^b​

Answer 1

HCF of 72 = 2^a × 3^b

=> 2×2×2×3×3 = 2^a×3^b

=> 2³ × 3² = 2^a × 3^b

Compare both sides , we get

a = 3 , b = 2

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