Question

find the kinetic energy of 2 moles of H2 atom at 300K (ideal gas)​

Answer 1

K.E.= 3/2nRT

which is

no. of moles=n

R= Gas constant

T= Temprature

Now,

K.E= 3/2×4.12×2×300

= 3,708 cal/mol

Is it correct?

I hope it helped..

tried my best