Question

find the kinetic energy potential energy Total energy Binding Energy of artificial satelite orbiting at a height 3600 km above the surface of earth.
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Answer 1

Answer:

Calculate the kinetic energy, potential energy, total energy and binding energy of an artificial satellite of mass 2000 kg orbiting at a height of 3600 km above the surface of the Earth. Given: G=6.67x10" Nm /kg R = 6400 km M=6x1024 kg [Ans: KE = 40.09 10%. PE = -80.09 10°J TE = 40.09 *10'), BE = 40.09 10°J]

Answer 2

Explanation:

Given:- G = 6.67 x 10-11 Nm²/kg2

R = 6400 km

M = 6 x 1024 kg

Given:- m = 2000 kg, h = 3600 km =

3.6 × 106 m,

G = 6.67 x 10-11 Nm²/kg²

R = 6400 km M = 6 x 1024 kg

To find :

i) Kinetic energy (K.E.)

ii) Potential Energy (P.E.)

From formula (ii),

P.E. = -2 x 40.02 × 10⁹ X

= -80.04 × 10⁹ J

iii) Total Energy (T.E.)

iv) Binding Energy (B.E.)

Formulae: i.

K.E. = GMm 2(R+h)

ii. P.E. == GMm (R+h) = -2(K.E.)

T.E.K.E. + P.E. iv. B.E. = -T.E.

Calculation: From formula (i),

6.67 x 10 x6x10²4 × 2 × 10³ 2x [(6.4×10)+(3.6x10*)] K.E. =

6.67×6×10¹6

10

= 40.02 × 10² J