Find the L.C.M and H.C.F of 404 and 96 and verify that L.C.M × H.C.F = Product of the two
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Answered by
14
Answer:
Step-by-step explanation:
Let a=404 and b=96
Expressing the number as a product of prime number
404=2×2×101
96=2×2×2×2×2×3
∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696
∴ HCF of 404 and 96 is 2×2=4
Now HCF×LCM=4×9696=38784
Product of two given numbers 404×96=38784
Hence HCM×LCM= product of two given numbers.
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Answered by
8
Answer:
The answer is
The prime factorization of 404 and 96 are:
404 = 2 × 2 × 101
96 = 2 × 2 × 2 × 2 × 2 × 3
The GCF of two or more numbers is the product of the prime factors common to all the numbers.
Therefore, required GCF = (2 × 2) = 4
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