Math, asked by pratheekcricket, 5 months ago

Find the L.C.M and H.C.F of 404 and 96 and verify that L.C.M × H.C.F = Product of the two

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Answers

Answered by Rithviksai2734
14

Answer:

Step-by-step explanation:

Let a=404 and b=96

Expressing the number as a product of prime number

404=2×2×101

96=2×2×2×2×2×3

∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696

∴ HCF of 404 and 96 is 2×2=4

Now HCF×LCM=4×9696=38784

Product of two given numbers 404×96=38784

Hence HCM×LCM= product of two given numbers.

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Answered by Rohit9904
8

Answer:

The answer is

The prime factorization of 404 and 96 are:

404 = 2 × 2 × 101

96 = 2 × 2 × 2 × 2 × 2 × 3

The GCF of two or more numbers is the product of the prime factors common to all the numbers.

Therefore, required GCF = (2 × 2) = 4

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