Question

Find the L.C.M and H.C.F of the following integers using 12,15,21
the prime factorization method
​

Answer 1

Answer: LCM AND HCF=420 and 3

Step-by-step explanation: prime factors of 12,15 and 21 are

12 = 2×2×3 = 2²×3

15 = 3×5

21=3×7

LCM can be taken by multiplying above factors = 2×2×3×3×3×5×7=2×2×3×5×7=420

HCF can be found by taking the common one out = 3

Hope it Helps!

Answer 2

Question:-

Find the L.C.M and H.C.F of the following integers using $12,15,21$ the prime factorization method.

Answer:-

Prime factors of $12,15 \: and 21$ are:-

$\implies$ $12=2×2×3=2²×3¹$

$\implies$ $15=3×5=3¹×5¹$

$\implies$ $21=3×7=3¹×7¹$

Now,

LCM of 12, 15 and 21 =$2²×3×5×7$

$\: \: \: \: \:$ =$4×3×5×7$

$\: \: \: \: \:$ =$\boxed{420}$

Now,

HCF of 12, 15 and 21=$\boxed{3}$

$\therefore$ LCM(12, 15 and 21)= $420$

And HCF(12, 15 and 21)= $3$

More To Know:-

• LCM or Least Common Multiple is smallest number which is divisible by given numbers.

• HCF or Highest Common Multiple is highest number divisible by given numbers.