Question

Find the L.C.M of 52 , 130 , and 455 by division method . ​

Answer 1

Answer:

\begin{gathered} \huge{\begin{array}{c|c} 2 & 52 , 130 , 455 \\ \cline{1-2} 2 & 26 , 65 , 455 \\ \cline{1-2} 5 & 13 , 65 , 455 \\ \cline{1-2} 7 & 13 , 13 , 91 \\ \cline{1-2} 13 & 13 , 13 , 13 \\ \cline{1-2} & 1 , 1 , 1 \end{array}}\end{gathered}

2

\cline1−22

\cline1−25

\cline1−27

\cline1−213

\cline1−2

52,130,455

26,65,455

13,65,455

13,13,91

13,13,13

1,1,1

\tt{ LCM = 2 \times 2 \times 5 \times 7 \times 13 }LCM=2×2×5×7×13

= 4 ×5 ×7 × 13

= 20 ×7 ×13

= 140 × 13

= 1820

therefore , LCM of 52, 130 , 455 = 1,820

Additional Information :

→ LCM × HCF = Product of two numbers

Ex - Take two numbers 2 and 12

LCM = 12

HCF = 2

2 × 12 = 12 × 2

24 = 24

hence , verified .

Answer 2

Answer:

☺️ Here is your answer dear ☺️

2 | 52 , 130 , 455

2 | 26 , 65 , 455

5 | 13 , 65 , 455

13 | 13 , 13 , 91

7 | 1 , 1 , 7

| 1 , 1 , 1

☺️ Hope it help you dear ☺️

Step-by-step explanation: