find the l.c.m of the following polynomial 4 x²(x+a)²,6a²x(x²-a²)and. 9 x³( x³-a³)
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Answer:
Given:
p(x)=12(x+1)(x−3)
q(x)=?
L.C.M =(x2−9)=(x+3)(x−3)
So, H.C.F = 2(x+1)2
Using the formula,
p(x)×q(x)=H.C.F×L.C.M
q(x)=12(x+1)(x−3)2(x+3)(x−3)(x+1)2
=6(x−3)(x+1)
Therefore, q(x) is 6(x−3)(x+1)
Step-by-step explanation:
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