Question

Find the L.C.M of X 2 + X, X 2 – 1, X 2 – X.

Answer 1

Step-by-step explanation:

LCM of x²+x. ; x²-1². ;x²-x

LCM of x(x+1) ; (x-1)(x+1) ;x(x-1)

They don't have common factors .

So LCM is equal to the product of these expressions

LCM=(x²+x)(x²-1)(x²-x)

=x(x+1)(x-1)(x+1)(x)(x-1)

=x²(x+1)²(x-1)²

=x²(x²-1)²

Answer 2

Step-by-step explanation:

x^2+ x = x (x+1)

x^2-1 = (x+1)(x-1)

x^2-x = x (x-1)

so lcm = x (x+1)(x-1) OR x (x^2-1)