Question

. Find the L.C.M of X2 + X, X2 – 1, X2-X.​

Answer 1

Answer:

x(x+1)(x-1)

x²+x=x(x+1)

x²-1=(x+1)(x-1)

x²-x=x(x-1)

ans=x(x+1)(x-1)

Answer 2

The given question is we have to find the LCM of

${x}^{2} + x \\ {x}^{2} - 1 \\ {x }^{2} - x$

The LCM stands for Least Common Multiplier.

First we have to find the factors of the above expression

${x}^{2} + x = x(x + 1) \\ {x}^{2} - 1 = (x + 1)(x - 1) \\ {x}^{2} - x = x(x - 1)$

Based on the above values,the LCM for these terms is

$x(x - 1)(x + 1).$

Hence, The LCM for the above expression is found.

#spj2.

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