Find the L.S.A and T.S.A. of prism given below. (a) 6cm 8cm 10cm
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Given: the base is a right angled triangle with sides a=6cm, b=8cm, c=10cm and T.S.A= 156^2cm
. We know that
T.S.A.=2B+Ph=2× 1/2×8×6+(6+8+10)h=48+24h.
Thus 48+24h=156. This implies that 24h=156−48=108.
Hence h= 24/108=4.5cm.
Therefore, LSA=Ph=(6+8+10)×4.5=24×4.5=108^2cm.
hope it help you
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