Question

Find the laplace transform of et Sin(t).

Answer 1

Answer:

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Answer 2

Concept

Use the laplace property will use to solve the problem

1. If $L\{f(t)\}=F(s)$ then $L\left\{e^{a t} f(t)\right\}=F(s-a)$.

2. $L\{\sin (t)\}=\frac{1}{s^{2}+1}$

Given

The expression is $e^tsint$

Find

We have to Find the laplace transform of the given expression.

Solution

Find the value of $L\{e^tsint\}$.

Apply the property of laplace.

$L\{e^tsint\}=L\{sint\}(s-1)$

                $=\frac{1}{(s-1)^2+1}$

Hence the value is $\frac{1}{(s-1)^2+1}$.