find the laplace transform of( sin2t-2tcos2t)
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Answer:
don't know
Step-by-step explanation:
khud se karo
Ur book pado
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0
Step-by-step explanation:
Lt[sin(2t)−2tcos(2t)](s)=2s2+4−2(s2−4)(s2+4)2=16(s2+4)2
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