Find the Laplace transform sin t sin 2t sin 3t
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Step-by-step explanation:
sin(2t)sin(3t)=12(cos(t)−cos(5t))
and that :
Lt[kcos(ωt)](s)=kss2+ω2
Hence we have :
Lt[sin(2t)sin(3t)](s)=Lt[12(cos(t)−cos(5t))]
(s)=12(ss2+1−ss2+25)=12ss4+26s2+25
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