Question

Find the laplace transform sin² (2t + 1)​

Answer 1

Chat defeated me! You are pretty much finished

2(2)=12−12(4)
s
i
n
2
(
2
t
)
=
1
2
−
1
2
c
o
s
(
4
t
)

Transforming
(2(2))=12(1)−12((4))=12(1)−12(2+16)
L
(
s
i
n
2
(
2
t
)
)
=
1
2
L
(
1
)
−
1
2
L
(
c
o
s
(
4
t
)
)
=
1
2
(
1
s
)
−
1
2
(
s
s
2
+
16
)