Question

find the largert noumber which divides 2053 and 967 and leaves a riminder 5 and 7 respectively.

Answer 1

2053-5=2048
967-7=960

Now find the HCF of 2048 and 960 by long division method.
The HCF of 2048 and 960 will be 64 which will be the largest number which divides 2053 and 967 by leaving remainder 5 and 7 respectively.
Hope it helped......

Answer 2

number divides 2053 and remainder is 5

so , number must be diviser of 2048

number divides 967 and remainder is 7

so , number must be diviser of 960


let us find common divisor of both ie hcf


2048 = 2 ×2×2×2×2×2×2×2×2×2×2

960 = 2× 2×2××2×2×2×3×5

so expected number is , 2× 2×2××2×2×2


= 64