Question

find the largest 3 digit number that is divisible by 12,15,and 18.

Answer 1

Answer:

900

Step-by-step explanation:

Since the no. is divisible by 12, 15 and 18

Therefore the no.is also divisible by LCM of the given nos.

12=2×2×3

15=3×5

18=2×3×3

LCM = 180

Largest 3 digit no. is 999

On dividing 999 by 180,we get

Remainder=99

On subtracting 99 from 999 we get

900

Therefore 900 is largest 3 digit no. divisible by 12,15 and 18

Hope this will help

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Answer 2

Answer:

Step-by-step explanation:

The LCM of 12, 15,18 is 180

Now the largest 3 digit number is 999

If we divide 999 by 180 we get 5 as Quotient and 99 as Remainder

So the largest 3 digit number which is divisible by 180 is 999 - 99 = 900

So the required number is = 900 + 5 = 905

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