Question

find the largest 4 digit number divisible by 15,21,28

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

LCM of 15, 21, 28 = 420

Largest 4-digit no. = 9999

Now, (largest 4 digit no.) ÷ (LCM of 15, 21, 28) = 9999 ÷ 420

Remainder = 339

So, largest 4-digit no. divisible by 15,21,28 = 9999 -339

                                                                      = 9660       (Ans )

HOPE THIS IS HELPFUL !!! : )