Question

Find the largest 4-digit number which is exactly divisible by 30​

Answer 1

The prime factorizations of 30 and 40 are 30 = 2 x 3 x 5 and 40 = 2 x 2 x 2 x 5, so their least common multiple is 2 x 2 x 2 x 3 x 5 = 120. Thus, any number evenly divisible by both 30 and 40 must be evenly divisible by 120. Since 10,000/120 gives a quotient between 83 and 84, the number we want must be 83 x 120, or 9,960. As a check, 9,960/30 = 332, and 9,960/40 = 249, exactly divisible!

Answer 2

Answer:

greatest four digit number divisible by both 30 and 40 is 9960

Step-by-step explanation:

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