Question

find the largest 4 digit number which when divided by 4,7 and 13 leaves the remainder of 3 in each case?​

Answer 1

Answer:

Since the (number-3) is divisible by 4 , 7 , 13. Hence :

(Number-3) = multiple of LCM of 4,7,13 = multiple of 364

So The number is = 364x , which lies between 1000 and 9999.

So on dividing 9999 by 364 we get remainder is 171. So we get to know that (number-3) = 9999-171

which is equal to 9828.

So the required number is = 9828+3

which is equal to 9831.

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