Question

find the largest 4- digit which is exactly divisible by 35
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Answer 1

Answer:

10000=100∗10010000=100∗100

Remainder of 100 with 35 = 30or−530or−5

Remainder of 10,000 with 35 = (-5)*(-5) = 25

Subtract 25 from 10,000 to get 9975!

The last 4-digit number divisible by 35 is 9975. This is sometimes also referred to as the largest four digit number divisible by 35 or the greatest 4-digit number divisible by 35.

Answer 2

To Find :- find the largest 4- digit which is exactly divisible by 35 ?

Concept used :-

• Largest four digit number = 9999
• Divide 9999 by 35 now .
• If we get some remainder . Subtract that remainder from 9999 .
• That will be required number .

Solution :-

→ Largest four digit number = 9999

now, dividing 9999 by 35 we get,

→ 99 = 35 × 2 + 29

→ 299 = 35 × 8 + 19

→ 199 = 35 × 5 + 24

then,

→ 9999 = 35 × 285 + 24

we get,

→ Quotient = 285

→ Remainder = 24

therefore, subtracting the remainder from 9999 we get,

→ 9999 - 24 = 9975 (Ans.)

Verification :-

→ 9975 = 35 × 285

Hence, the largest 4- digit which is exactly divisible by 35 is equal to 9975 .

Learn more :-

let a and b positive integers such that 90 less than a+b less than 99 and 0.9 less than a/b less than 0.91. Find ab/46

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