Question

find the largest 6 digit no exactly divisible by 10,15 and 20

Answer 1

LCM of 10,15 and 20=60
smallest 6 digit number=100,000
but it is not divisible by 60
therefore, largest 6 digit number divisible by 60 is 100,000+20=100,020
We got it by first dividing 100,000 by60, and subtracting the remainder and adding 60 to it from the smallest 6 digit number .

Hope it helps.
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Answer 2

Answer:

The required number is 999960 which is exactly divisible by 10,15 and 20.

Step-by-step explanation:

To find : The Greatest 5 digit number exactly divisible by 9 and 13?

Solution :  

The greatest 6-digit number is 999999.

Now, Find the LCM of 10,15 and 20.

2 | 10  15  20

2 |  5   15  10

3 |  5   15   5

5 |  5    5   5

  |  1     1     1

$LCM(10,15,20)=2\times 2\times 3\times 5$

$LCM(10,15,20)=60$

Divide 999999 by 60 so that we get the remainder,

$999999 = 16666 \times 60 + 39$

Remainder is 39.

Now, Subtract the remainder from 999999.

$999999-39=999960$

Therefore, The required number is 999960 which is exactly divisible by 10,15 and 20.