Question

find the largest 6 digit number exactly divisible by 18, 24, 36​

Answer 1

Answer:

999936 this is the largest 6 digit number exactly divisible by 18, 24, 36

Answer 2

Answer:

LCM of 18,24 and 36

18 = 2 × ${3}^2$

24 = ${2}^3$ × 3

36 = ${3}^2$ ×   ${2}^2$

LCM (18,24,36) =   ${2}^3$ × ${3}^2$

= 72

Largest 6 digit number is 999999

Now divide 999999 by 72

You will get 63 as remainder

Required Number = 999999 – 63  

= 999936