Find the largest digit number exactly divisible by ech of the numbers 12.15, 18 and 27.
Answers
Answered by
2
Answer:
540
Step-by-step explanation:
For the answer we have to find LCM
2 | 12,15,18,27
3 | 6,15,9,27
3 | 2,5,3,9
| 2,5,1,3
LCM= 2×3×3×2×5×1×3
= 540
Ans.- The largest digit number exactly divisible by each of the numbers 12,15,18 and 27 is 540.
Similar questions