Math, asked by aditya06panda, 5 months ago

Find the largest divisor of 1001001001 that does not exceed 1000. (You may assume that 9901 is a prime number)

PS: pls do not answer I you do not know (for getting points)​

Answers

Answered by cpsinghmnq
2

Answer:

707.

10001001001 = 7*11*13*101*9901

9901 is prime, it is more than 1000, so it can not participate in the product.

If 101 participates in the product, it can only do so with 7, because multiplying 101 by 11 or 13 makes more than 1000.

7*11*13 = 1001 >1000. This does not work. Any two number out of 7,11,13, when multiplied by each other, give less than 707..

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