Find the largest four-digit number which when divided by 4, 7 and 13
leaves a remainder of 3 in each case.
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Answer:
he answer is 9831
Step-by-step explanation:
7 and 13 are prime numbers. LCM ( 4, 7, 13) = 364 We know that, the largest 4 digit number is 9999
9999/364 = 171
9999 9999 – 171 = 9828
9828 + 3 = 9831
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