Find the largest four-digit number which when divided by 4, 7, and 13 leaves a.remainder of 3 in each case,
Answers
Answered by
1
Step-by-step explanation:
Prime factors of 4,7 and 13
4=2×2
7 and 13 are prime numbers
LCM (4,7,13)=36
we know that, the largest 4 digit number is 9999.
Step 1 : divide 9999 by 364, we get
364
9999
=171
Step 2: subtract 171 from 9999
9999−171=9828
Since a remainder of 3 is to be left
9282+3=9831
therefore 9831 is the number.
Answered by
0
Answer:
9831
Step-by-step explanation:
Prime factors of 4,7 and 13
4=2×2
7 and 13 are prime numbers
LCM (4,7,13)=36
we know that, the largest 4 digit number is 9999.
Step 1 : divide 9999 by 364, we get
364
9999
=171
Step 2: subtract 171 from 9999
9999−171=9828
Since a remainder of 3 is to be left
9282+3=9831
therefore 9831 is the number.
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