Math, asked by ashishsharama07, 4 months ago

find the largest namber that will divide 398,436 and 542 leaveing remaindrs7,11 and 15 respectively.​

Answers

Answered by TessaAnn
0

Answer:

We have , → The number 398, 436 and 542 which when divides by a positive integers leaves remainder as 7, 11, and 15 respectively . → Clearly, the required number divides ( 398 - 7 ) = 391 , ( 436 - 11 ) = 425, and ( 542 - 15 ) = 527 exactly

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