Find the largest no that divides 1251, 9377, 15628 leaving remainder 1,2,3respectively
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subtract 1,2,3 from 1251, 9377,15628 respectively.
1251-1=1250,
9377-2=9375,
15628-3=15625
find the hcf of 1250 and 9375
9375= 1250*7+625
1250=625*2+0
thus 625 is the hcf
now, find the hcf of 625 and 15625
15625=625*25+0
thus 625 is the number that divides 1251,9377 and 15628 leaving the remainders 1,2 and 3 respective
1251-1=1250,
9377-2=9375,
15628-3=15625
find the hcf of 1250 and 9375
9375= 1250*7+625
1250=625*2+0
thus 625 is the hcf
now, find the hcf of 625 and 15625
15625=625*25+0
thus 625 is the number that divides 1251,9377 and 15628 leaving the remainders 1,2 and 3 respective
Haripriyahp:
If 15625 didnt get r = 0 by dividing by 625 then again we have to do division and which no comes in divisor as r=0 is hcf right
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